The 25th Cyprus Open international backgammon tournament has reached a crucial stage, with two Iranian players set to face each other among the final 12 competitors.
According to the published tournament bracket, Milad Momeni and Omid Badiei are scheduled to compete head-to-head. The matchup is notable because both players are Iranian, although Omid Badiei is listed under the Swedish flag and Milad Momeni under the Iranian flag in the tournament system.
Milad Momeni vs. Omid Badiei in the Last 12
One of the key matchups in this stage is the contest between Omid Badiei and Milad Momeni. Both players have progressed through the earlier rounds to reach the last 12, and they must now compete against each other to secure their place in the next stage.
The published bracket currently shows a 0–0 score, with no winner recorded yet.
Two Iranian Players Reach the Final Stage of the Cyprus Open
The presence of Milad Momeni and Omid Badiei among the final 12 players is a notable development for Iranian competitors in this edition of the tournament. Since the two players are facing each other directly, only one can advance and continue competing for a higher position.
It remains to be seen which player will win this matchup and maintain their place in the 25th Cyprus Open.
Fans can follow the tournament bracket and updated results through the official FTBgsystem platform.